Punnett Square - dihybrid cross
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Dihybrid Cross - the gametes
We have looked at how to derive the haploid gametes in a monohybrid cross - we are now going to look at how to derive the gametes for a dihybrid cross.
In a dihybrid cross you have two alleles that you wish to follow, let's call them 'A' and 'B'. So, this means that 'A' would be dominant, and 'a' would be recessive; and 'B' would be dominant and 'b' would be recessive. The different genotypes would be represented as AABB, AaBB etc.
1) For an AaBb individual how many different genotypes of gametes would be produced?
One answer only.
   1
   2
   3
   4
   5
   8
   10
   12
   16
   32
2) For a dihybrid cross how many different combinations of alleles are there potentially?
One answer only.
   1
   2
   3
   4
   5
   8
   10
   12
   16
   32
The Punnett Square Calculator cannot automatically work out the gametes for you, but it can perform the crosses, hence you need to know what gametes to put in, AND you must understand how the calculation works as you won't have the calculator available in exams (plus you should NEVER trust a computer to do a calculation that you don't understand).
A dihybrid example
You wish to perform a dihybrid cross with an organism that has 2 legs, and 2 eyes. You know that one allele is dominant and produces an animal with 4 legs, and the other is recessive and produces an animal with 4 eyes.
1) If 'A' represents the gene for 4 legs, and 'B' the gene for 2 eyes, which of the following would be heterozygous for 4 legs?
One answer only.
   aABB
   aabb
   AABB
   AABb
2) Which of the following would be homozygous for four eyes?
One answer only.
   aABB
   aabb
   AABB
   AABb
3) If you crossed a 2 eyed, 2 legged homozygote with a homozygote 4 legged, 4 eyed. If you use A or a for legs and B or b for eyes, what would the offspring be?
One answer only.
   AABB
   AaBB
   aaBB
   Aabb
   aabb
   AAbb
   aABb
   All the above are possible.
   None of the above are possible
   It would be a mixture of AABB and AaBB
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