# Empirical formula

(Difference between revisions)
 Revision as of 18:40, 1 December 2018 (view source)m (added one more example and fixed some formatting)← Older edit Latest revision as of 11:54, 3 December 2018 (view source)Nnjm2 (Talk | contribs) Line 1: Line 1: − The empirical formula of a substance is its simplest whole number ratio between its constituents. The Molecular Formula is a multiple of the Empirical Formula. + The empirical formula of a substance is its simplest whole number ratio between its constituents. The [[Molecular Formula|Molecular Formula]] is a multiple of the Empirical Formula. − For example:  + For example: − The Molecular formula of butanoic acid is C4H8O2 whilst the empirical formula is C2H4O.  + The molecular formula of [[butanoic acid|butanoic acid]] is C4H8O2 whilst the empirical formula is C2H4O. − + − + To calculate Empirical Formula: To calculate Empirical Formula: −  Mass (g) / Relative Atomic Mass (Ar)  → This will give you the number of moles. + Mass (g) / Relative Atomic Mass (Ar) → This will give you the number of moles. −  You then divide the number of moles by the smallest number reulting from your previous calculations, and that will give you the ratio for the empirical formula. + You then divide the number of moles by the smallest number resulting from your previous calculations, and that will give you the ratio for the empirical formula. − + −
+ Example: Example: − You have 9.62 g of Carbon, 1.60 g of Hydrogen and 4.28 g of Oxygen. What is the empirical formula of this CHO substance? + You have 9.62 g of [[carbon|carbon]], 1.60 g of [[hydrogen|hydrogen]] and 4.28 g of [[oxygen|oxygen]]. What is the empirical formula of this CHO substance? − C → 9.62 / 12.01 (Ar) = 0.80 (number of moles) + C → 9.62 / 12.01 (Ar) = 0.80 (number of moles) − H → 1.60 / 1.01 = 1.60 + H → 1.60 / 1.01 = 1.60 − O → 4.28 / 16.00 = 0.27 + O → 4.28 / 16.00 = 0.27 Smallest value = 0.27, so: Smallest value = 0.27, so: − C → 0.80 / 0.27 = 2.96  + C → 0.80 / 0.27 = 2.96 − + − H → 1.60 / 0.27 = 5.93 + − O → 0.27 / 0.27 = 1 + H → 1.60 / 0.27 = 5.93 −
+ O → 0.27 / 0.27 = 1 − Empirical formula uses whole numbers, so you must round the numbers obtained to the closest whole number. This gives us an empirical formula of: + The Empirical formula uses whole numbers, so you must round the numbers obtained to the closest whole number. This gives us an empirical formula of: C3H6O C3H6O

## Latest revision as of 11:54, 3 December 2018

The empirical formula of a substance is its simplest whole number ratio between its constituents. The Molecular Formula is a multiple of the Empirical Formula.

For example:

The molecular formula of butanoic acid is C4H8O2 whilst the empirical formula is C2H4O.

To calculate Empirical Formula:

Mass (g) / Relative Atomic Mass (Ar) → This will give you the number of moles.

You then divide the number of moles by the smallest number resulting from your previous calculations, and that will give you the ratio for the empirical formula.

Example:

You have 9.62 g of carbon, 1.60 g of hydrogen and 4.28 g of oxygen. What is the empirical formula of this CHO substance?

C → 9.62 / 12.01 (Ar) = 0.80 (number of moles)

H → 1.60 / 1.01 = 1.60

O → 4.28 / 16.00 = 0.27

Smallest value = 0.27, so:

C → 0.80 / 0.27 = 2.96

H → 1.60 / 0.27 = 5.93

O → 0.27 / 0.27 = 1

The Empirical formula uses whole numbers, so you must round the numbers obtained to the closest whole number. This gives us an empirical formula of:

C3H6O